Please help me, i have a table with this record & query.

SELECT DISTINCT
	aa.id,
	aa.id_user,
	aa.id_outlet,
	aa.array_tanggal as plan_date
FROM
	visit_plan_outlet AS aa
WHERE
	aa.array_tanggal IS NOT NULL
LIMIT 10

id id_user id_outlet plan_date

20	1309	166	[5,21,25]
21	1309	175	[6,26]
22	1309	171	[1,25]
23	1309	178	[6,26]
24	1309	186	[8,28]
25	1309	184	[7,11]
26	1309	183	[7,27]
27	1309	195	[8,28]
28	1309	196	[11,29]
29	1309	257	[14]

My question is: How to show record with plan_date same with current date ? with laravel, not using LIKE because if we use like sample:

$current_date = date('j'); //Exp: Date One (1)

aa.array_date LIKE '$current_date'

But show record too: (This wrong)

20	1309	166	[5,21,25]
22	1309	171	[1,25]
25	1309	184	[7,11]
28	1309	196	[11,29]
29	1309	257	[14]

Must be shown:

22	1309	171	[1,25]