I have this function:
public function show($id)
{
if (count($post = Post::find($id))) {
$post = $post->load(['comments' => function ($q) {
$q->latest();
$q->with(['author' => function ($q) {
$q->select('id', 'username');
}]);
}, 'user' => function ($q) {
$q->select('id', 'username');
}]);
$this->authorize('seePost', $post);
return view('post.show', ['post' => $post]);
} else {
dd('no post');
}
}
I added the if statement as if I try to open a route to a non existent post id I get the error Call to a member function load() on null. However now I have two queries, one looks for the Post in the DB and if it finds one then I have to load the relations with the second one. What can I do to go back to just one query with all the relations loaded and avoid the error? Any clue?
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